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4.6d=54-d^2
We move all terms to the left:
4.6d-(54-d^2)=0
We get rid of parentheses
d^2+4.6d-54=0
a = 1; b = 4.6; c = -54;
Δ = b2-4ac
Δ = 4.62-4·1·(-54)
Δ = 237.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.6)-\sqrt{237.16}}{2*1}=\frac{-4.6-\sqrt{237.16}}{2} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.6)+\sqrt{237.16}}{2*1}=\frac{-4.6+\sqrt{237.16}}{2} $
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